What are the solutions to the equation 3x^2+19x^2+21x+5=0 ?

The solutions to the equation 3x^2+19x^2+21x+5=0 are x=-5/11 ,x=-1/2

Find the zeros of 3x^2+19x^2+21x+5=0

The zeros of 3x^2+19x^2+21x+5=0 are x=-5/11 ,x=-1/2

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3 x^{2} + 19 x^{2} + 21 x + 5 = 0

x = - \frac{5}{11}, x = - \frac{1}{2}

Decimal Notation

x = - 0.45454 \dots, x = - 0.5

Solution steps

3 x^{2} + 19 x^{2} + 21 x + 5 = 0

Refine

22 x^{2} + 21 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 22 \cdot 5}{2 \cdot 22}

2 1^{2} - 4 \cdot 22 \cdot 5 = 1

x_{1, 2} = \frac{- 21 \pm 1}{2 \cdot 22}

Separate the solutions

x_{1} = \frac{- 21 + 1}{2 \cdot 22}, x_{2} = \frac{- 21 - 1}{2 \cdot 22}

x = \frac{- 21 + 1}{2 \cdot 22} : - \frac{5}{11}

x = \frac{- 21 - 1}{2 \cdot 22} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{11}, x = - \frac{1}{2}

- 2 x^{2} - 3 = 5 x^{2} + 25

x^{2} + 5 - 6 = 0

x^{2} + 7 x + 8 = 0

(3 y - 10)^{2} + y^{2} = 10

x, - 3 x y^{2} - 2 x^{2} y + 8 x y = 0

What are the solutions to the equation 3x^2+19x^2+21x+5=0 ?
The solutions to the equation 3x^2+19x^2+21x+5=0 are x=-5/11 ,x=-1/2
Find the zeros of 3x^2+19x^2+21x+5=0
The zeros of 3x^2+19x^2+21x+5=0 are x=-5/11 ,x=-1/2