What are the solutions to the equation sqrt(10)^2=1^2+x^2 ?

The solutions to the equation sqrt(10)^2=1^2+x^2 are x=3,x=-3

Find the zeros of sqrt(10)^2=1^2+x^2

The zeros of sqrt(10)^2=1^2+x^2 are x=3,x=-3

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10^{2} = 1^{2} + x^{2}

x = 3, x = - 3

Solution steps

(10)^{2} = 1^{2} + x^{2}

Switch sides

1^{2} + x^{2} = (10)^{2}

Move

1^{2}

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

8 x^{2} = 648

x, (x + 1)^{2} + (y - 4)^{2} = 0

x^{2} + 2.8 = 23.04

x^{2} + 8 x + 13 = - 2 x - 8

p^{2} + 12 p - 54

What are the solutions to the equation sqrt(10)^2=1^2+x^2 ?
The solutions to the equation sqrt(10)^2=1^2+x^2 are x=3,x=-3
Find the zeros of sqrt(10)^2=1^2+x^2
The zeros of sqrt(10)^2=1^2+x^2 are x=3,x=-3