What are the solutions to the equation solvefor x,2ax^2+4ax-6a=0 ?

The solutions to the equation solvefor x,2ax^2+4ax-6a=0 are x=1,x=-3;\quad a\ne 0

Find the zeros of solvefor x,2ax^2+4ax-6a=0

The zeros of solvefor x,2ax^2+4ax-6a=0 are x=1,x=-3;\quad a\ne 0

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x, 2 a x^{2} + 4 a x - 6 a = 0

x = 1, x = - 3; a \neq = 0

Solution steps

2 a x^{2} + 4 a x - 6 a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 a \pm ( 4 a ) ^{2} - 4 \cdot 2 a ( - 6 a )}{2 \cdot 2 a}

Simplify

(4 a)^{2} - 4 \cdot 2 a (- 6 a) : 8 a

x_{1, 2} = \frac{- 4 a \pm 8 a}{2 \cdot 2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- 4 a + 8 a}{2 \cdot 2 a}, x_{2} = \frac{- 4 a - 8 a}{2 \cdot 2 a}

x = \frac{- 4 a + 8 a}{2 \cdot 2 a} : 1

x = \frac{- 4 a - 8 a}{2 \cdot 2 a} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3; a \neq = 0

x^{2} + 10 x + 25 = 9

2 x - x^{2} = x

t, 2 s = g t^{2} + v t

x^{2} + 10 x + 24 = 3

- 2 t (t + 3) = - 7

What are the solutions to the equation solvefor x,2ax^2+4ax-6a=0 ?
The solutions to the equation solvefor x,2ax^2+4ax-6a=0 are x=1,x=-3;\quad a\ne 0
Find the zeros of solvefor x,2ax^2+4ax-6a=0
The zeros of solvefor x,2ax^2+4ax-6a=0 are x=1,x=-3;\quad a\ne 0