What are the solutions to the equation 3x^2=2-x ?

The solutions to the equation 3x^2=2-x are x= 2/3 ,x=-1

Find the zeros of 3x^2=2-x

The zeros of 3x^2=2-x are x= 2/3 ,x=-1

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3 x^{2} = 2 - x

x = \frac{2}{3}, x = - 1

Decimal Notation

x = 0.66666 \dots, x = - 1

Solution steps

3 x^{2} = 2 - x

Move

x

to the left side

3 x^{2} + x = 2

Move

2

to the left side

3 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 3}, x_{2} = \frac{- 1 - 5}{2 \cdot 3}

x = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

x^{2} - x + \frac{5}{2} = 0

1 + x^{2} = 16

x^{2} + 13 x + 40 = 0

(x + 3) (x - 1) = (4 x - 1) (2 x + 3)

5 - (x + 3)^{2} = x

What are the solutions to the equation 3x^2=2-x ?
The solutions to the equation 3x^2=2-x are x= 2/3 ,x=-1
Find the zeros of 3x^2=2-x
The zeros of 3x^2=2-x are x= 2/3 ,x=-1