What are the solutions to the equation 4x^2-x-7=0 ?

The solutions to the equation 4x^2-x-7=0 are x=(1+sqrt(113))/8 ,x=(1-sqrt(113))/8

Find the zeros of 4x^2-x-7=0

The zeros of 4x^2-x-7=0 are x=(1+sqrt(113))/8 ,x=(1-sqrt(113))/8

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4 x^{2} - x - 7 = 0

x = \frac{1 + 113}{8}, x = \frac{1 - 113}{8}

Decimal Notation

x = 1.45376 \dots, x = - 1.20376 \dots

Solution steps

4 x^{2} - x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 (- 7) = 113

x_{1, 2} = \frac{- ( - 1 ) \pm 113}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 113}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 113}{2 \cdot 4}

x = \frac{- ( - 1 ) + 113}{2 \cdot 4} : \frac{1 + 113}{8}

x = \frac{- ( - 1 ) - 113}{2 \cdot 4} : \frac{1 - 113}{8}

The solutions to the quadratic equation are:

x = \frac{1 + 113}{8}, x = \frac{1 - 113}{8}

x^{2} - 6 x + 8.5 = 0

w^{2} - 18 w

(x - (3 + 7)) (x - (3 - 7)) = 0

- 39.662 x^{2} + 548.12 x - 564.5 = 548.12

2 x^{2} = 3 x + 54

What are the solutions to the equation 4x^2-x-7=0 ?
The solutions to the equation 4x^2-x-7=0 are x=(1+sqrt(113))/8 ,x=(1-sqrt(113))/8
Find the zeros of 4x^2-x-7=0
The zeros of 4x^2-x-7=0 are x=(1+sqrt(113))/8 ,x=(1-sqrt(113))/8