What are the solutions to the equation 9x^2+24x-7=0 ?

The solutions to the equation 9x^2+24x-7=0 are x=(-4+sqrt(23))/3 ,x=-(4+sqrt(23))/3

Find the zeros of 9x^2+24x-7=0

The zeros of 9x^2+24x-7=0 are x=(-4+sqrt(23))/3 ,x=-(4+sqrt(23))/3

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9 x^{2} + 24 x - 7 = 0

x = \frac{- 4 + 23}{3}, x = - \frac{4 + 23}{3}

Decimal Notation

x = 0.26527 \dots, x = - 2.93194 \dots

Solution steps

9 x^{2} + 24 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 ( - 7 )}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 (- 7) = 623

x_{1, 2} = \frac{- 24 \pm 6 23}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 24 + 6 23}{2 \cdot 9}, x_{2} = \frac{- 24 - 6 23}{2 \cdot 9}

x = \frac{- 24 + 6 23}{2 \cdot 9} : \frac{- 4 + 23}{3}

x = \frac{- 24 - 6 23}{2 \cdot 9} : - \frac{4 + 23}{3}

The solutions to the quadratic equation are:

x = \frac{- 4 + 23}{3}, x = - \frac{4 + 23}{3}

2 x^{2} = 3 x - 10

a, (a^{3} + 27) = (a + 3) (a^{2} + ma + 9)

6 x^{2} - 84 x + 228 = 0

x^{2} - 6 x + 12

x^{2} + 6 x - 4

What are the solutions to the equation 9x^2+24x-7=0 ?
The solutions to the equation 9x^2+24x-7=0 are x=(-4+sqrt(23))/3 ,x=-(4+sqrt(23))/3
Find the zeros of 9x^2+24x-7=0
The zeros of 9x^2+24x-7=0 are x=(-4+sqrt(23))/3 ,x=-(4+sqrt(23))/3