What are the solutions to the equation 5x=4x^2-2 ?

The solutions to the equation 5x=4x^2-2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8

Find the zeros of 5x=4x^2-2

The zeros of 5x=4x^2-2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8

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5 x = 4 x^{2} - 2

x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

Decimal Notation

x = 1.56872 \dots, x = - 0.31872 \dots

Solution steps

5 x = 4 x^{2} - 2

Switch sides

4 x^{2} - 2 = 5 x

Move

5 x

to the left side

4 x^{2} - 2 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 2) = 57

x_{1, 2} = \frac{- ( - 5 ) \pm 57}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 57}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 57}{2 \cdot 4}

x = \frac{- ( - 5 ) + 57}{2 \cdot 4} : \frac{5 + 57}{8}

x = \frac{- ( - 5 ) - 57}{2 \cdot 4} : \frac{5 - 57}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

y, (y + 1)^{2} = (2 - x) ln (x)

4 x^{2} - 6 x + 9

2 r^{2} + 8 r - 19 = 0

(- \frac{3}{2})^{2} + (\frac{1}{2})^{2} = r^{2}

3 x^{2} - 6 x + 2 = 0

What are the solutions to the equation 5x=4x^2-2 ?
The solutions to the equation 5x=4x^2-2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8
Find the zeros of 5x=4x^2-2
The zeros of 5x=4x^2-2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8