What are the solutions to the equation m^2+4m+8=0 ?

The solutions to the equation m^2+4m+8=0 are m=-2+2i,m=-2-2i

Find the zeros of m^2+4m+8=0

The zeros of m^2+4m+8=0 are m=-2+2i,m=-2-2i

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m^{2} + 4 m + 8 = 0

m = - 2 + 2 i, m = - 2 - 2 i

Solution steps

m^{2} + 4 m + 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 8 : 4 i

m_{1, 2} = \frac{- 4 \pm 4 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 4 i}{2 \cdot 1}, m_{2} = \frac{- 4 - 4 i}{2 \cdot 1}

m = \frac{- 4 + 4 i}{2 \cdot 1} : - 2 + 2 i

m = \frac{- 4 - 4 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

m = - 2 + 2 i, m = - 2 - 2 i

x, (2 x + j^{3} y)^{2} - 6 - j^{12} = 0

0 = x^{2} - 2 x + 6

x^{2} - 20 x + 72 = - 3 x - 3 x

x, 2 x^{2} + 5 x + 3 = 0

2 - 9 x + 10 x^{2} = 0

What are the solutions to the equation m^2+4m+8=0 ?
The solutions to the equation m^2+4m+8=0 are m=-2+2i,m=-2-2i
Find the zeros of m^2+4m+8=0
The zeros of m^2+4m+8=0 are m=-2+2i,m=-2-2i