What are the solutions to the equation x^2+x-7=5 ?

The solutions to the equation x^2+x-7=5 are x=3,x=-4

Find the zeros of x^2+x-7=5

The zeros of x^2+x-7=5 are x=3,x=-4

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x^{2} + x - 7 = 5

x = 3, x = - 4

Solution steps

x^{2} + x - 7 = 5

Move

5

to the left side

x^{2} + x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 1}, x_{2} = \frac{- 1 - 7}{2 \cdot 1}

x = \frac{- 1 + 7}{2 \cdot 1} : 3

x = \frac{- 1 - 7}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

s^{2} + 4 s + 12 = 0

2 x^{2} + 7 x = - 1

4 x^{2} - 40 x + 84 = 0

x^{2} + 4 x + (- 1) = 0

x, f = x^{2} + y^{2} + x (y - z) - 4 x - 6 y + 4 z + 30

What are the solutions to the equation x^2+x-7=5 ?
The solutions to the equation x^2+x-7=5 are x=3,x=-4
Find the zeros of x^2+x-7=5
The zeros of x^2+x-7=5 are x=3,x=-4