What are the solutions to the equation 8x^2=4 ?

The solutions to the equation 8x^2=4 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 8x^2=4

The zeros of 8x^2=4 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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8 x^{2} = 4

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

8 x^{2} = 4

Divide both sides by

8

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

80 = 80 t - 16 t^{2}

(22 + 3) x^{2} - (22 + 4) x + 2 = 0

x^{2} - 3 x - 24 = 0

\frac{1}{3} x^{2} = 16

9 x^{2} - 36 x + 1 = 0

What are the solutions to the equation 8x^2=4 ?
The solutions to the equation 8x^2=4 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 8x^2=4
The zeros of 8x^2=4 are x= 1/(sqrt(2)),x=-1/(sqrt(2))