What are the solutions to the equation y^2-y+1/4 =0 ?

The solutions to the equation y^2-y+1/4 =0 are y= 1/2

Find the zeros of y^2-y+1/4 =0

The zeros of y^2-y+1/4 =0 are y= 1/2

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y^{2} - y + \frac{1}{4} = 0

y = \frac{1}{2}

Decimal

y = 0.5

Solution steps

y^{2} - y + \frac{1}{4} = 0

Multiply both sides by

4

4 y^{2} - 4 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

y_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

y = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

y = \frac{1}{2}

The solution to the quadratic equation is:

y = \frac{1}{2}

x^{2} > 11 - 4 x

6 d - \frac{11}{2} = 2 d - \frac{13}{2}

1 - \frac{365 !}{36 5 ^{23} ( 365 - 23 ) !}

(3 a - b)^{2} + 3 (a + b)^{2}

x^{2} + 8 = 84

What are the solutions to the equation y^2-y+1/4 =0 ?
The solutions to the equation y^2-y+1/4 =0 are y= 1/2
Find the zeros of y^2-y+1/4 =0
The zeros of y^2-y+1/4 =0 are y= 1/2