What are the solutions to the equation 4m^2+8m+3=0 ?

The solutions to the equation 4m^2+8m+3=0 are m=-1/2 ,m=-3/2

Find the zeros of 4m^2+8m+3=0

The zeros of 4m^2+8m+3=0 are m=-1/2 ,m=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 m^{2} + 8 m + 3 = 0

m = - \frac{1}{2}, m = - \frac{3}{2}

Decimal Notation

m = - 0.5, m = - 1.5

Solution steps

4 m^{2} + 8 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 3 = 4

m_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 8 + 4}{2 \cdot 4}, m_{2} = \frac{- 8 - 4}{2 \cdot 4}

m = \frac{- 8 + 4}{2 \cdot 4} : - \frac{1}{2}

m = \frac{- 8 - 4}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

m = - \frac{1}{2}, m = - \frac{3}{2}

21 x^{2} + 48 x - 144 = 0

(x - 9)^{2} = 80

(x - 1)^{2} + 3 x = x + 26

6 x (x + 8) = 0

t, s = t^{2} - 5 t + 10

What are the solutions to the equation 4m^2+8m+3=0 ?
The solutions to the equation 4m^2+8m+3=0 are m=-1/2 ,m=-3/2
Find the zeros of 4m^2+8m+3=0
The zeros of 4m^2+8m+3=0 are m=-1/2 ,m=-3/2