What are the solutions to the equation 8n^2+47n+50=-3n ?

The solutions to the equation 8n^2+47n+50=-3n are n=-5/4 ,n=-5

Find the zeros of 8n^2+47n+50=-3n

The zeros of 8n^2+47n+50=-3n are n=-5/4 ,n=-5

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8 n^{2} + 47 n + 50 = - 3 n

n = - \frac{5}{4}, n = - 5

Decimal Notation

n = - 1.25, n = - 5

Solution steps

8 n^{2} + 47 n + 50 = - 3 n

Move

3 n

to the left side

8 n^{2} + 50 n + 50 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 8 \cdot 50}{2 \cdot 8}

5 0^{2} - 4 \cdot 8 \cdot 50 = 30

n_{1, 2} = \frac{- 50 \pm 30}{2 \cdot 8}

Separate the solutions

n_{1} = \frac{- 50 + 30}{2 \cdot 8}, n_{2} = \frac{- 50 - 30}{2 \cdot 8}

n = \frac{- 50 + 30}{2 \cdot 8} : - \frac{5}{4}

n = \frac{- 50 - 30}{2 \cdot 8} : - 5

The solutions to the quadratic equation are:

n = - \frac{5}{4}, n = - 5

[3 (x + 10)]^{2} + [3 x]^{2} = 20 0^{2}

\frac{3 x ^{2}}{8} = x - \frac{12}{24}

- 2 x^{2} + 7 x - 9 = 0

(x + 4) (x - 4) = 9

(m - 1) x^{2} - (m^{2} + 7 m - 5) x + 5 m - 9 = 0

What are the solutions to the equation 8n^2+47n+50=-3n ?
The solutions to the equation 8n^2+47n+50=-3n are n=-5/4 ,n=-5
Find the zeros of 8n^2+47n+50=-3n
The zeros of 8n^2+47n+50=-3n are n=-5/4 ,n=-5