What are the solutions to the equation 0=(x-1)(x+1) ?

The solutions to the equation 0=(x-1)(x+1) are x=1,x=-1

Find the zeros of 0=(x-1)(x+1)

The zeros of 0=(x-1)(x+1) are x=1,x=-1

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0 = (x - 1) (x + 1)

x = 1, x = - 1

Solution steps

0 = (x - 1) (x + 1)

Switch sides

(x - 1) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = 1, x = - 1

w^{2} + 4 w - 96 = 0

16 = (x - 4) (x + 2)

t^{2} - 8 t - 20 = 0

384 = - 16 t^{2} + 160 t

b^{2} = 12 (b - 3)

What are the solutions to the equation 0=(x-1)(x+1) ?
The solutions to the equation 0=(x-1)(x+1) are x=1,x=-1
Find the zeros of 0=(x-1)(x+1)
The zeros of 0=(x-1)(x+1) are x=1,x=-1