What is 2\sqrt[3]{6}*2^{2/3}x^5\sqrt[3]{x} ?

The solution to 2\sqrt[3]{6}*2^{2/3}x^5\sqrt[3]{x} is 4*3^{1/3}x^{16/3}

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simplify 2\sqrt[3]{6}*2^{2/3}x^5\sqrt[3]{x}

simplify

4 \cdot 3^{\frac{1}{3}} x^{\frac{16}{3}}

Solution steps

Simplify

2 \cdot 2^{\frac{2}{3}} = 2^{\frac{5}{3}}

Factor integer

6 = 2 \cdot 3

Apply exponent rule:

(ab)^{c} = a^{c} b^{c}

= 2^{\frac{5}{3}} \cdot 2^{\frac{1}{3}} \cdot 3^{\frac{1}{3}} x^{\frac{16}{3}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{5}{3}} \cdot 2^{\frac{1}{3}} = 2^{\frac{5}{3} + \frac{1}{3}}

= 2^{\frac{5}{3} + \frac{1}{3}} \cdot 3^{\frac{1}{3}} x^{\frac{16}{3}}

2^{\frac{5}{3} + \frac{1}{3}} = 2^{2}

= 2^{2} \cdot 3^{\frac{1}{3}} x^{\frac{16}{3}}

2^{2} = 4

= 4 \cdot 3^{\frac{1}{3}} x^{\frac{16}{3}}

y^{2} - 9 x^{2}

∣ 5 y - 5 ∣ = ∣ 4 y + 6 ∣

\frac{x}{5} + 4 > - 3

(x + 8) (x + 15) = 0

x^{2} + (x + 1)^{2} + (x + 2)^{2} + (x + 3)^{2} = 54

What is 2\sqrt[3]{6}*2^{2/3}x^5\sqrt[3]{x} ?
The solution to 2\sqrt[3]{6}*2^{2/3}x^5\sqrt[3]{x} is 4*3^{1/3}x^{16/3}