What are the solutions to the equation 8m^2+48m=0 ?

The solutions to the equation 8m^2+48m=0 are m=0,m=-6

Find the zeros of 8m^2+48m=0

The zeros of 8m^2+48m=0 are m=0,m=-6

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8 m^{2} + 48 m = 0

m = 0, m = - 6

Solution steps

8 m^{2} + 48 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

4 8^{2} - 4 \cdot 8 \cdot 0 = 48

m_{1, 2} = \frac{- 48 \pm 48}{2 \cdot 8}

Separate the solutions

m_{1} = \frac{- 48 + 48}{2 \cdot 8}, m_{2} = \frac{- 48 - 48}{2 \cdot 8}

m = \frac{- 48 + 48}{2 \cdot 8} : 0

m = \frac{- 48 - 48}{2 \cdot 8} : - 6

The solutions to the quadratic equation are:

m = 0, m = - 6

2 z^{2} - z + 1 = 0

z^{2} + 24 = 11 z

t, s = - 15.45 t^{2} - 1.302 t + 5.234

3 x^{2} - 7 x = x^{2} - 14 x - 4

25 x^{2} + 36 = 60 x

What are the solutions to the equation 8m^2+48m=0 ?
The solutions to the equation 8m^2+48m=0 are m=0,m=-6
Find the zeros of 8m^2+48m=0
The zeros of 8m^2+48m=0 are m=0,m=-6