What are the solutions to the equation -1x^2-2x+3=0 ?

The solutions to the equation -1x^2-2x+3=0 are x=-3,x=1

Find the zeros of -1x^2-2x+3=0

The zeros of -1x^2-2x+3=0 are x=-3,x=1

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- 1 x^{2} - 2 x + 3 = 0

x = - 3, x = 1

Solution steps

- 1 \cdot x^{2} - 2 x + 3 = 0

Refine

- x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 3 = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4}{2 ( - 1 )} : - 3

x = \frac{- ( - 2 ) - 4}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 3, x = 1

r, A = \frac{1}{2} r^{2} θ

ab x^{2} - a^{2} x - b^{2} x + ab = 0

0.042 x^{2} + x - 18 = 0

2 = 3 x^{2} + 1

10 x^{2} + 18 x = 0

What are the solutions to the equation -1x^2-2x+3=0 ?
The solutions to the equation -1x^2-2x+3=0 are x=-3,x=1
Find the zeros of -1x^2-2x+3=0
The zeros of -1x^2-2x+3=0 are x=-3,x=1