What are the solutions to the equation 4x^2+5x-7=0 ?

The solutions to the equation 4x^2+5x-7=0 are x=(-5+sqrt(137))/8 ,x=(-5-sqrt(137))/8

Find the zeros of 4x^2+5x-7=0

The zeros of 4x^2+5x-7=0 are x=(-5+sqrt(137))/8 ,x=(-5-sqrt(137))/8

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4 x^{2} + 5 x - 7 = 0

x = \frac{- 5 + 137}{8}, x = \frac{- 5 - 137}{8}

Decimal Notation

x = 0.83808 \dots, x = - 2.08808 \dots

Solution steps

4 x^{2} + 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 7) = 137

x_{1, 2} = \frac{- 5 \pm 137}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 137}{2 \cdot 4}, x_{2} = \frac{- 5 - 137}{2 \cdot 4}

x = \frac{- 5 + 137}{2 \cdot 4} : \frac{- 5 + 137}{8}

x = \frac{- 5 - 137}{2 \cdot 4} : \frac{- 5 - 137}{8}

The solutions to the quadratic equation are:

x = \frac{- 5 + 137}{8}, x = \frac{- 5 - 137}{8}

x, \int y d y = x^{2}

x, (f \circ g) = x^{2}

4 y^{2} - 28 y + 49 = 0

5 x^{2} - 34 x + 24 = 0

x, x^{2} y = x^{2} - 4

What are the solutions to the equation 4x^2+5x-7=0 ?
The solutions to the equation 4x^2+5x-7=0 are x=(-5+sqrt(137))/8 ,x=(-5-sqrt(137))/8
Find the zeros of 4x^2+5x-7=0
The zeros of 4x^2+5x-7=0 are x=(-5+sqrt(137))/8 ,x=(-5-sqrt(137))/8