What are the solutions to the equation 6t^2+7t+2=0 ?

The solutions to the equation 6t^2+7t+2=0 are t=-1/2 ,t=-2/3

Find the zeros of 6t^2+7t+2=0

The zeros of 6t^2+7t+2=0 are t=-1/2 ,t=-2/3

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6 t^{2} + 7 t + 2 = 0

t = - \frac{1}{2}, t = - \frac{2}{3}

Decimal Notation

t = - 0.5, t = - 0.66666 \dots

Solution steps

6 t^{2} + 7 t + 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

7^{2} - 4 \cdot 6 \cdot 2 = 1

t_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 6}

Separate the solutions

t_{1} = \frac{- 7 + 1}{2 \cdot 6}, t_{2} = \frac{- 7 - 1}{2 \cdot 6}

t = \frac{- 7 + 1}{2 \cdot 6} : - \frac{1}{2}

t = \frac{- 7 - 1}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

t = - \frac{1}{2}, t = - \frac{2}{3}

a, a^{2} - 2 ab + b^{2} + c^{2} = 0

x^{2} + (\frac{- 1}{2})^{2} = 1

- 8 x^{2} - 11 x - 2 = 0

\frac{( x + 2 ) ^{2}}{9} = \frac{2}{3} - \frac{( x + 3 ) ( x - 3 )}{5}

2 x^{2} + 3 x - 2 = 3

What are the solutions to the equation 6t^2+7t+2=0 ?
The solutions to the equation 6t^2+7t+2=0 are t=-1/2 ,t=-2/3
Find the zeros of 6t^2+7t+2=0
The zeros of 6t^2+7t+2=0 are t=-1/2 ,t=-2/3