What are the solutions to the equation 25+8x-x^2=0 ?

The solutions to the equation 25+8x-x^2=0 are x=4-sqrt(41),x=4+sqrt(41)

Find the zeros of 25+8x-x^2=0

The zeros of 25+8x-x^2=0 are x=4-sqrt(41),x=4+sqrt(41)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 + 8 x - x^{2} = 0

x = 4 - 41, x = 4 + 41

Decimal Notation

x = - 2.40312 \dots, x = 10.40312 \dots

Solution steps

25 + 8 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 8 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 25}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 25 = 241

x_{1, 2} = \frac{- 8 \pm 2 41}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 41}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 41}{2 ( - 1 )}

x = \frac{- 8 + 2 41}{2 ( - 1 )} : 4 - 41

x = \frac{- 8 - 2 41}{2 ( - 1 )} : 4 + 41

The solutions to the quadratic equation are:

x = 4 - 41, x = 4 + 41

x, x^{2} - y^{2} + z^{2} = 1

s, t = \frac{3}{5} s^{2} + 3 s + 1

7 x^{2} + 5 x - 8

- 2 x^{2} = 2

- 2 x^{2} = 6

What are the solutions to the equation 25+8x-x^2=0 ?
The solutions to the equation 25+8x-x^2=0 are x=4-sqrt(41),x=4+sqrt(41)
Find the zeros of 25+8x-x^2=0
The zeros of 25+8x-x^2=0 are x=4-sqrt(41),x=4+sqrt(41)