What are the solutions to the equation 10r^2-2r-19=0 ?

The solutions to the equation 10r^2-2r-19=0 are r=(1+sqrt(191))/(10),r=(1-sqrt(191))/(10)

Find the zeros of 10r^2-2r-19=0

The zeros of 10r^2-2r-19=0 are r=(1+sqrt(191))/(10),r=(1-sqrt(191))/(10)

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10 r^{2} - 2 r - 19 = 0

r = \frac{1 + 191}{10}, r = \frac{1 - 191}{10}

Decimal Notation

r = 1.48202 \dots, r = - 1.28202 \dots

Solution steps

10 r^{2} - 2 r - 19 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 ( - 19 )}{2 \cdot 10}

(- 2)^{2} - 4 \cdot 10 (- 19) = 2191

r_{1, 2} = \frac{- ( - 2 ) \pm 2 191}{2 \cdot 10}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 2 191}{2 \cdot 10}, r_{2} = \frac{- ( - 2 ) - 2 191}{2 \cdot 10}

r = \frac{- ( - 2 ) + 2 191}{2 \cdot 10} : \frac{1 + 191}{10}

r = \frac{- ( - 2 ) - 2 191}{2 \cdot 10} : \frac{1 - 191}{10}

The solutions to the quadratic equation are:

r = \frac{1 + 191}{10}, r = \frac{1 - 191}{10}

x^{2} - 18 x + 68 = 0

a^{2} + 7^{2} = 9^{2}

16 x^{2} = 64

x^{2} = 3 x^{2}

X^{2} = 169

What are the solutions to the equation 10r^2-2r-19=0 ?
The solutions to the equation 10r^2-2r-19=0 are r=(1+sqrt(191))/(10),r=(1-sqrt(191))/(10)
Find the zeros of 10r^2-2r-19=0
The zeros of 10r^2-2r-19=0 are r=(1+sqrt(191))/(10),r=(1-sqrt(191))/(10)