What are the solutions to the equation 4m^2+9=0 ?

The solutions to the equation 4m^2+9=0 are m= 3/2 i,m=-3/2 i

Find the zeros of 4m^2+9=0

The zeros of 4m^2+9=0 are m= 3/2 i,m=-3/2 i

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4 m^{2} + 9 = 0

m = \frac{3}{2} i, m = - \frac{3}{2} i

Solution steps

4 m^{2} + 9 = 0

Move

9

to the right side

4 m^{2} = - 9

Divide both sides by

4

m^{2} = - \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - \frac{9}{4}, m = - - \frac{9}{4}

- \frac{9}{4} = \frac{3}{2} i

- - \frac{9}{4} = - \frac{3}{2} i

m = \frac{3}{2} i, m = - \frac{3}{2} i

(x + 1)^{2} = x^{2} + (x - 1)^{2}

x^{2} + 12 x + 36 = 0

x^{2} - 14 x = 24

(x + 2)^{2} = - 18

x^{2} - 2 x + 4 = 6

What are the solutions to the equation 4m^2+9=0 ?
The solutions to the equation 4m^2+9=0 are m= 3/2 i,m=-3/2 i
Find the zeros of 4m^2+9=0
The zeros of 4m^2+9=0 are m= 3/2 i,m=-3/2 i