What are the solutions to the equation λ^2-1.6λ+0.6=0 ?

The solutions to the equation λ^2-1.6λ+0.6=0 are λ=1,λ= 3/5

Find the zeros of λ^2-1.6λ+0.6=0

The zeros of λ^2-1.6λ+0.6=0 are λ=1,λ= 3/5

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λ^{2} - 1.6 λ + 0.6 = 0

λ = 1, λ = \frac{3}{5}

Decimal Notation

λ = 1, λ = 0.6

Solution steps

λ^{2} - 1.6 λ + 0.6 = 0

Multiply both sides by

10

10 λ^{2} - 16 λ + 6 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 10 \cdot 6}{2 \cdot 10}

(- 16)^{2} - 4 \cdot 10 \cdot 6 = 4

λ_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 10}

Separate the solutions

λ_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 10}, λ_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 10}

λ = \frac{- ( - 16 ) + 4}{2 \cdot 10} : 1

λ = \frac{- ( - 16 ) - 4}{2 \cdot 10} : \frac{3}{5}

The solutions to the quadratic equation are:

λ = 1, λ = \frac{3}{5}

X^{2} - 12 X + 27 = 0

4 = 4 x - x^{2}

- 5 x^{2} + 2 x + 3 = 0

x^{2} - 10 x - 200 = 0

x^{(2)} - 5 x - 2 = 0

What are the solutions to the equation λ^2-1.6λ+0.6=0 ?
The solutions to the equation λ^2-1.6λ+0.6=0 are λ=1,λ= 3/5
Find the zeros of λ^2-1.6λ+0.6=0
The zeros of λ^2-1.6λ+0.6=0 are λ=1,λ= 3/5