What are the solutions to the equation 9y^2+21y-18=0 ?

The solutions to the equation 9y^2+21y-18=0 are y= 2/3 ,y=-3

Find the zeros of 9y^2+21y-18=0

The zeros of 9y^2+21y-18=0 are y= 2/3 ,y=-3

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9 y^{2} + 21 y - 18 = 0

y = \frac{2}{3}, y = - 3

Decimal Notation

y = 0.66666 \dots, y = - 3

Solution steps

9 y^{2} + 21 y - 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 9 ( - 18 )}{2 \cdot 9}

2 1^{2} - 4 \cdot 9 (- 18) = 33

y_{1, 2} = \frac{- 21 \pm 33}{2 \cdot 9}

Separate the solutions

y_{1} = \frac{- 21 + 33}{2 \cdot 9}, y_{2} = \frac{- 21 - 33}{2 \cdot 9}

y = \frac{- 21 + 33}{2 \cdot 9} : \frac{2}{3}

y = \frac{- 21 - 33}{2 \cdot 9} : - 3

The solutions to the quadratic equation are:

y = \frac{2}{3}, y = - 3

16 x^{2} + 32 x

15 + 2 y = y^{2}

x^{2} + 8 x + 9

x^{2} + 8 x + 1

22 = 2 + 37 t - 16 t^{2}

What are the solutions to the equation 9y^2+21y-18=0 ?
The solutions to the equation 9y^2+21y-18=0 are y= 2/3 ,y=-3
Find the zeros of 9y^2+21y-18=0
The zeros of 9y^2+21y-18=0 are y= 2/3 ,y=-3