What are the solutions to the equation -2x^2+16x-30=0 ?

The solutions to the equation -2x^2+16x-30=0 are x=3,x=5

Find the zeros of -2x^2+16x-30=0

The zeros of -2x^2+16x-30=0 are x=3,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 16 x - 30 = 0

x = 3, x = 5

Solution steps

- 2 x^{2} + 16 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 2 ) ( - 30 )}{2 ( - 2 )}

1 6^{2} - 4 (- 2) (- 30) = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 ( - 2 )}, x_{2} = \frac{- 16 - 4}{2 ( - 2 )}

x = \frac{- 16 + 4}{2 ( - 2 )} : 3

x = \frac{- 16 - 4}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = 3, x = 5

19 m^{2} = 8 m

2 x^{2} - 8 x = 4

2 x^{2} - 8 x = 3

6 x^{2} + 11 x + 5 = 0

x^{2} + 10 = 154

What are the solutions to the equation -2x^2+16x-30=0 ?
The solutions to the equation -2x^2+16x-30=0 are x=3,x=5
Find the zeros of -2x^2+16x-30=0
The zeros of -2x^2+16x-30=0 are x=3,x=5