What are the solutions to the equation t^2-3t-10=0 ?

The solutions to the equation t^2-3t-10=0 are t=5,t=-2

Find the zeros of t^2-3t-10=0

The zeros of t^2-3t-10=0 are t=5,t=-2

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t^{2} - 3 t - 10 = 0

t = 5, t = - 2

Solution steps

t^{2} - 3 t - 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

t_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, t_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

t = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

t = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

t = 5, t = - 2

x^{2} + 8 x + 12 = 0

2 x^{2} + 28 x + 82 = 0

2 X^{2} + 8 = 0

2 x (x - 5) = (5 - 5)^{2}

x, 2 x^{2} + y^{3} = 0

What are the solutions to the equation t^2-3t-10=0 ?
The solutions to the equation t^2-3t-10=0 are t=5,t=-2
Find the zeros of t^2-3t-10=0
The zeros of t^2-3t-10=0 are t=5,t=-2