What are the solutions to the equation 3m(2m+9)=0 ?

The solutions to the equation 3m(2m+9)=0 are m=0,m=-9/2

Find the zeros of 3m(2m+9)=0

The zeros of 3m(2m+9)=0 are m=0,m=-9/2

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3 m (2 m + 9) = 0

m = 0, m = - \frac{9}{2}

Decimal Notation

m = 0, m = - 4.5

Solution steps

3 m (2 m + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m = 0 or 2 m + 9 = 0

Solve

2 m + 9 = 0 : m = - \frac{9}{2}

The solutions to the quadratic equation are:

m = 0, m = - \frac{9}{2}

4 x^{2} + 1 = 5

6 r^{2} + 6 r + 12 = 0

(200 + 4 x) (50 + x) = 10000

3 x^{2} - 54 x + 186 = 0

x^{2} + \frac{3}{2} x - \frac{1}{4} = 0

What are the solutions to the equation 3m(2m+9)=0 ?
The solutions to the equation 3m(2m+9)=0 are m=0,m=-9/2
Find the zeros of 3m(2m+9)=0
The zeros of 3m(2m+9)=0 are m=0,m=-9/2