What are the solutions to the equation -1/2 x^2-2x+6=0 ?

The solutions to the equation -1/2 x^2-2x+6=0 are x=-6,x=2

Find the zeros of -1/2 x^2-2x+6=0

The zeros of -1/2 x^2-2x+6=0 are x=-6,x=2

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- \frac{1}{2} x^{2} - 2 x + 6 = 0

x = - 6, x = 2

Solution steps

- \frac{1}{2} x^{2} - 2 x + 6 = 0

Multiply both sides by

2

- x^{2} - 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) \cdot 12}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) \cdot 12 = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 8}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 8}{2 ( - 1 )} : - 6

x = \frac{- ( - 4 ) - 8}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 6, x = 2

(130 π \cdot 1 0^{3} - w)^{2} = 3 \cdot 150 π \cdot 1 0^{3}

4 x^{2} + 7 = 0

4 x + 12 x^{2} = 0

0 = 2 x^{2} - 6 x

4 x^{2} - 9 x^{2} - 36 = 0

What are the solutions to the equation -1/2 x^2-2x+6=0 ?
The solutions to the equation -1/2 x^2-2x+6=0 are x=-6,x=2
Find the zeros of -1/2 x^2-2x+6=0
The zeros of -1/2 x^2-2x+6=0 are x=-6,x=2