What are the solutions to the equation 3x^2-196x+2376=0 ?

The solutions to the equation 3x^2-196x+2376=0 are x=(2(49+sqrt(619)))/3 ,x=(2(49-sqrt(619)))/3

Find the zeros of 3x^2-196x+2376=0

The zeros of 3x^2-196x+2376=0 are x=(2(49+sqrt(619)))/3 ,x=(2(49-sqrt(619)))/3

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3 x^{2} - 196 x + 2376 = 0

x = \frac{2 ( 49 + 619 )}{3}, x = \frac{2 ( 49 - 619 )}{3}

Decimal Notation

x = 49.25314 \dots, x = 16.08019 \dots

Solution steps

3 x^{2} - 196 x + 2376 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 196 ) \pm ( - 196 ) ^{2} - 4 \cdot 3 \cdot 2376}{2 \cdot 3}

(- 196)^{2} - 4 \cdot 3 \cdot 2376 = 4619

x_{1, 2} = \frac{- ( - 196 ) \pm 4 619}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 196 ) + 4 619}{2 \cdot 3}, x_{2} = \frac{- ( - 196 ) - 4 619}{2 \cdot 3}

x = \frac{- ( - 196 ) + 4 619}{2 \cdot 3} : \frac{2 ( 49 + 619 )}{3}

x = \frac{- ( - 196 ) - 4 619}{2 \cdot 3} : \frac{2 ( 49 - 619 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 49 + 619 )}{3}, x = \frac{2 ( 49 - 619 )}{3}

(3 x - 2)^{2} = x^{2} + (2 x + 2)^{2}

12 x^{2} - 240 x + 864 = 0

x, Z = x^{2} + y^{2}

2 (x - 4)^{2} = - 5

6 x^{2} - 72 x = 0

What are the solutions to the equation 3x^2-196x+2376=0 ?
The solutions to the equation 3x^2-196x+2376=0 are x=(2(49+sqrt(619)))/3 ,x=(2(49-sqrt(619)))/3
Find the zeros of 3x^2-196x+2376=0
The zeros of 3x^2-196x+2376=0 are x=(2(49+sqrt(619)))/3 ,x=(2(49-sqrt(619)))/3