What are the solutions to the equation 0=-4.9t^2+27t ?

The solutions to the equation 0=-4.9t^2+27t are t=0,t= 270/49

Find the zeros of 0=-4.9t^2+27t

The zeros of 0=-4.9t^2+27t are t=0,t= 270/49

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 4.9 t^{2} + 27 t

t = 0, t = \frac{270}{49}

Decimal Notation

t = 0, t = 5.51020 \dots

Solution steps

0 = - 4.9 t^{2} + 27 t

Multiply both sides by

10

0 = - 49 t^{2} + 270 t

Switch sides

- 49 t^{2} + 270 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 270 \pm 27 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

27 0^{2} - 4 (- 49) \cdot 0 = 270

t_{1, 2} = \frac{- 270 \pm 270}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 270 + 270}{2 ( - 49 )}, t_{2} = \frac{- 270 - 270}{2 ( - 49 )}

t = \frac{- 270 + 270}{2 ( - 49 )} : 0

t = \frac{- 270 - 270}{2 ( - 49 )} : \frac{270}{49}

The solutions to the quadratic equation are:

t = 0, t = \frac{270}{49}

- 6 x^{2} = x^{2} - 28

x + 1 = (3 x - 1)^{2}

x, x^{2} - 4 x + 13 = 0

n^{2} - \frac{1}{2} n = 3 n + 16

(2 x + 2) (6 \times (- 1)) = (3 x - 3) (4 x - 1)

What are the solutions to the equation 0=-4.9t^2+27t ?
The solutions to the equation 0=-4.9t^2+27t are t=0,t= 270/49
Find the zeros of 0=-4.9t^2+27t
The zeros of 0=-4.9t^2+27t are t=0,t= 270/49