What are the solutions to the equation (x+2)(2x-3)=0 ?

The solutions to the equation (x+2)(2x-3)=0 are x=-2,x= 3/2

Find the zeros of (x+2)(2x-3)=0

The zeros of (x+2)(2x-3)=0 are x=-2,x= 3/2

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(x + 2) (2 x - 3) = 0

x = - 2, x = \frac{3}{2}

Decimal Notation

x = - 2, x = 1.5

Solution steps

(x + 2) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 2 x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = - 2, x = \frac{3}{2}

x, \frac{x ^{2}}{3 ^{2}} + \frac{z ^{2}}{4 ^{2}} = 0

10 x^{2} + 6 = 0

- 3 x^{2} = - 7 x - 20

2 π r^{2} + 36 π r - 357 = 0

- 3 x^{2} - 6 x + 21 = 6 x + 8

What are the solutions to the equation (x+2)(2x-3)=0 ?
The solutions to the equation (x+2)(2x-3)=0 are x=-2,x= 3/2
Find the zeros of (x+2)(2x-3)=0
The zeros of (x+2)(2x-3)=0 are x=-2,x= 3/2