What are the solutions to the equation (x+1)^2=e^2 ?

The solutions to the equation (x+1)^2=e^2 are x=e-1,x=-e-1

Find the zeros of (x+1)^2=e^2

The zeros of (x+1)^2=e^2 are x=e-1,x=-e-1

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(x + 1)^{2} = e^{2}

x = e - 1, x = - e - 1

Decimal Notation

x = 1.71828 \dots, x = - 3.71828 \dots

Solution steps

(x + 1)^{2} = e^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = e^{2} : x = e - 1

Solve

x + 1 = - e^{2} : x = - e - 1

The solutions to the quadratic equation are:

x = e - 1, x = - e - 1

4 x^{2} + 8 x = 20

- 3 = 5 - d^{2}

x, x^{2} - y^{2} + z^{2} - 4 x - 2 y - 2 z + 4 = 0

4 x^{2} + 3 x + 2

2 x^{2} + 11 x = - 12

What are the solutions to the equation (x+1)^2=e^2 ?
The solutions to the equation (x+1)^2=e^2 are x=e-1,x=-e-1
Find the zeros of (x+1)^2=e^2
The zeros of (x+1)^2=e^2 are x=e-1,x=-e-1