What are the solutions to the equation 6x^2+4x-6=0 ?

The solutions to the equation 6x^2+4x-6=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3

Find the zeros of 6x^2+4x-6=0

The zeros of 6x^2+4x-6=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3

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6 x^{2} + 4 x - 6 = 0

x = \frac{- 1 + 10}{3}, x = - \frac{1 + 10}{3}

Decimal Notation

x = 0.72075 \dots, x = - 1.38742 \dots

Solution steps

6 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 6) = 410

x_{1, 2} = \frac{- 4 \pm 4 10}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 4 + 4 10}{2 \cdot 6}, x_{2} = \frac{- 4 - 4 10}{2 \cdot 6}

x = \frac{- 4 + 4 10}{2 \cdot 6} : \frac{- 1 + 10}{3}

x = \frac{- 4 - 4 10}{2 \cdot 6} : - \frac{1 + 10}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 10}{3}, x = - \frac{1 + 10}{3}

- 4.9 t^{2} + 24.5 t + 117.6 = 0

x^{2} - 7 x + 2 = 0

- 2 x^{2} - 10 x + 100 = 0

x^{2} - 14 x - 15 = 0

49 - 16 x^{2} = 0

What are the solutions to the equation 6x^2+4x-6=0 ?
The solutions to the equation 6x^2+4x-6=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3
Find the zeros of 6x^2+4x-6=0
The zeros of 6x^2+4x-6=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3