What are the solutions to the equation -2.5^2+4.5^2=c^2 ?

The solutions to the equation -2.5^2+4.5^2=c^2 are c=sqrt(14),c=-sqrt(14)

Find the zeros of -2.5^2+4.5^2=c^2

The zeros of -2.5^2+4.5^2=c^2 are c=sqrt(14),c=-sqrt(14)

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- 2. 5^{2} + 4. 5^{2} = c^{2}

c = 14, c = - 14

Decimal Notation

c = 3.74165 \dots, c = - 3.74165 \dots

Solution steps

- 2. 5^{2} + 4. 5^{2} = c^{2}

Switch sides

c^{2} = - 2. 5^{2} + 4. 5^{2}

Simplify

- 2. 5^{2} + 4. 5^{2} : 14

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 14, c = - 14

x + 7 = x^{2} - 10 x + 25

t^{2} + 2 t = 8

2 x^{2} + 22 x + 13 = - 23

b, x^{2} + a x y + y^{2} = b^{2}

25 - 5 t - 2 t^{2} = 10 - 3 t - t^{2}

What are the solutions to the equation -2.5^2+4.5^2=c^2 ?
The solutions to the equation -2.5^2+4.5^2=c^2 are c=sqrt(14),c=-sqrt(14)
Find the zeros of -2.5^2+4.5^2=c^2
The zeros of -2.5^2+4.5^2=c^2 are c=sqrt(14),c=-sqrt(14)