What are the solutions to the equation 9m^2+234m+79=0 ?

The solutions to the equation 9m^2+234m+79=0 are m=(-39+sqrt(1442))/3 ,m=-(39+sqrt(1442))/3

Find the zeros of 9m^2+234m+79=0

The zeros of 9m^2+234m+79=0 are m=(-39+sqrt(1442))/3 ,m=-(39+sqrt(1442))/3

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9 m^{2} + 234 m + 79 = 0

m = \frac{- 39 + 1442}{3}, m = - \frac{39 + 1442}{3}

Decimal Notation

m = - 0.34210 \dots, m = - 25.65789 \dots

Solution steps

9 m^{2} + 234 m + 79 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 234 \pm 23 4 ^{2} - 4 \cdot 9 \cdot 79}{2 \cdot 9}

23 4^{2} - 4 \cdot 9 \cdot 79 = 61442

m_{1, 2} = \frac{- 234 \pm 6 1442}{2 \cdot 9}

Separate the solutions

m_{1} = \frac{- 234 + 6 1442}{2 \cdot 9}, m_{2} = \frac{- 234 - 6 1442}{2 \cdot 9}

m = \frac{- 234 + 6 1442}{2 \cdot 9} : \frac{- 39 + 1442}{3}

m = \frac{- 234 - 6 1442}{2 \cdot 9} : - \frac{39 + 1442}{3}

The solutions to the quadratic equation are:

m = \frac{- 39 + 1442}{3}, m = - \frac{39 + 1442}{3}

x^{2} = - 125

5 (x^{2} + 1) = 3 x^{2} + 7

x, x^{2} - 3 x y + y^{2} = 5

4 x^{2} - 17 x - 10 = 5

3 x^{2} - 2 x + 9 = (x + 3)^{2}

What are the solutions to the equation 9m^2+234m+79=0 ?
The solutions to the equation 9m^2+234m+79=0 are m=(-39+sqrt(1442))/3 ,m=-(39+sqrt(1442))/3
Find the zeros of 9m^2+234m+79=0
The zeros of 9m^2+234m+79=0 are m=(-39+sqrt(1442))/3 ,m=-(39+sqrt(1442))/3