What are the solutions to the equation x^2+6x-28=0 ?

The solutions to the equation x^2+6x-28=0 are x=-3+sqrt(37),x=-3-sqrt(37)

Find the zeros of x^2+6x-28=0

The zeros of x^2+6x-28=0 are x=-3+sqrt(37),x=-3-sqrt(37)

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x^{2} + 6 x - 28 = 0

x = - 3 + 37, x = - 3 - 37

Decimal Notation

x = 3.08276 \dots, x = - 9.08276 \dots

Solution steps

x^{2} + 6 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 28) = 237

x_{1, 2} = \frac{- 6 \pm 2 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 37}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 37}{2 \cdot 1}

x = \frac{- 6 + 2 37}{2 \cdot 1} : - 3 + 37

x = \frac{- 6 - 2 37}{2 \cdot 1} : - 3 - 37

The solutions to the quadratic equation are:

x = - 3 + 37, x = - 3 - 37

3 x - 2 - x^{2} = 0

- 0.5 x^{2} + 40 x - 350 = 0

7 z - 9 z^{2} = - 4

2 (9 - 3 x^{2}) = 0

q^{2} - 100 = 0

What are the solutions to the equation x^2+6x-28=0 ?
The solutions to the equation x^2+6x-28=0 are x=-3+sqrt(37),x=-3-sqrt(37)
Find the zeros of x^2+6x-28=0
The zeros of x^2+6x-28=0 are x=-3+sqrt(37),x=-3-sqrt(37)