What are the solutions to the equation x^2-14x+20=3 ?

The solutions to the equation x^2-14x+20=3 are x=7+4sqrt(2),x=7-4sqrt(2)

Find the zeros of x^2-14x+20=3

The zeros of x^2-14x+20=3 are x=7+4sqrt(2),x=7-4sqrt(2)

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x^{2} - 14 x + 20 = 3

x = 7 + 42, x = 7 - 42

Decimal Notation

x = 12.65685 \dots, x = 1.34314 \dots

Solution steps

x^{2} - 14 x + 20 = 3

Move

3

to the left side

x^{2} - 14 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 17 = 82

x_{1, 2} = \frac{- ( - 14 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8 2}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8 2}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8 2}{2 \cdot 1} : 7 + 42

x = \frac{- ( - 14 ) - 8 2}{2 \cdot 1} : 7 - 42

The solutions to the quadratic equation are:

x = 7 + 42, x = 7 - 42

- x^{2} + 13 x - 5 = 7 x

0 = x^{2} - 3 x - 3

0 = x^{2} - 3 x + 5

x^{2} + 18 x = - 77

49 x^{2} + 24 = - 70 x

What are the solutions to the equation x^2-14x+20=3 ?
The solutions to the equation x^2-14x+20=3 are x=7+4sqrt(2),x=7-4sqrt(2)
Find the zeros of x^2-14x+20=3
The zeros of x^2-14x+20=3 are x=7+4sqrt(2),x=7-4sqrt(2)