What are the solutions to the equation 12^2+3^2=x^2 ?

The solutions to the equation 12^2+3^2=x^2 are x=3sqrt(17),x=-3sqrt(17)

Find the zeros of 12^2+3^2=x^2

The zeros of 12^2+3^2=x^2 are x=3sqrt(17),x=-3sqrt(17)

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1 2^{2} + 3^{2} = x^{2}

x = 317, x = - 317

Decimal Notation

x = 12.36931 \dots, x = - 12.36931 \dots

Solution steps

1 2^{2} + 3^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 3^{2}

Simplify

1 2^{2} + 3^{2} : 153

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 153, x = - 153

153 = 317

- 153 = - 317

x = 317, x = - 317

2 x^{2} + 3 = 5 x

x, x^{2} + 4 y^{2} = 7 + 3 x y

15 x^{2} - 6 x - 3 = - 2 x

x^{2} + 1 = \frac{5 x}{2}

x, 4 x^{2} - 8 x + 3 = 0

What are the solutions to the equation 12^2+3^2=x^2 ?
The solutions to the equation 12^2+3^2=x^2 are x=3sqrt(17),x=-3sqrt(17)
Find the zeros of 12^2+3^2=x^2
The zeros of 12^2+3^2=x^2 are x=3sqrt(17),x=-3sqrt(17)