What are the solutions to the equation quadraticformula 4x^2-20x+25=0 ?

The solutions to the equation quadraticformula 4x^2-20x+25=0 are x= 5/2

Find the zeros of quadraticformula 4x^2-20x+25=0

The zeros of quadraticformula 4x^2-20x+25=0 are x= 5/2

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4 x^{2} - 20 x + 25 = 0

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

4 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

(3 s + 9)^{2} = 25

(3 - 2 x)^{2} = 70

5 x^{2} + 4 x = 6

3 x^{2} + 12 x = - 1

3 x^{2} + 12 x = 39

What are the solutions to the equation quadraticformula 4x^2-20x+25=0 ?
The solutions to the equation quadraticformula 4x^2-20x+25=0 are x= 5/2
Find the zeros of quadraticformula 4x^2-20x+25=0
The zeros of quadraticformula 4x^2-20x+25=0 are x= 5/2