What are the solutions to the equation (2x-6)(x-4)(4)=72 ?

The solutions to the equation (2x-6)(x-4)(4)=72 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2

Find the zeros of (2x-6)(x-4)(4)=72

The zeros of (2x-6)(x-4)(4)=72 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 6) (x - 4) (4) = 72

x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

Decimal Notation

x = 6.54138 \dots, x = 0.45861 \dots

Solution steps

(2 x - 6) (x - 4) (4) = 72

Expand

(2 x - 6) (x - 4) (4) : 8 x^{2} - 56 x + 96

8 x^{2} - 56 x + 96 = 72

Move

72

to the left side

8 x^{2} - 56 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 8 \cdot 24}{2 \cdot 8}

(- 56)^{2} - 4 \cdot 8 \cdot 24 = 837

x_{1, 2} = \frac{- ( - 56 ) \pm 8 37}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 56 ) + 8 37}{2 \cdot 8}, x_{2} = \frac{- ( - 56 ) - 8 37}{2 \cdot 8}

x = \frac{- ( - 56 ) + 8 37}{2 \cdot 8} : \frac{7 + 37}{2}

x = \frac{- ( - 56 ) - 8 37}{2 \cdot 8} : \frac{7 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

x^{2} + 32 x + 256 = 0

0 = - x^{2} + 4 x - 3

(x + 2)^{2} = \frac{3}{2}

(3 x + 1)^{2} = x + 2

x, y^{2} = - 6 x^{2} + c

What are the solutions to the equation (2x-6)(x-4)(4)=72 ?
The solutions to the equation (2x-6)(x-4)(4)=72 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2
Find the zeros of (2x-6)(x-4)(4)=72
The zeros of (2x-6)(x-4)(4)=72 are x=(7+sqrt(37))/2 ,x=(7-sqrt(37))/2