What are the solutions to the equation 8x^2+33x+4=0 ?

The solutions to the equation 8x^2+33x+4=0 are x=-1/8 ,x=-4

Find the zeros of 8x^2+33x+4=0

The zeros of 8x^2+33x+4=0 are x=-1/8 ,x=-4

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8 x^{2} + 33 x + 4 = 0

x = - \frac{1}{8}, x = - 4

Decimal Notation

x = - 0.125, x = - 4

Solution steps

8 x^{2} + 33 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 \cdot 8 \cdot 4}{2 \cdot 8}

3 3^{2} - 4 \cdot 8 \cdot 4 = 31

x_{1, 2} = \frac{- 33 \pm 31}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 33 + 31}{2 \cdot 8}, x_{2} = \frac{- 33 - 31}{2 \cdot 8}

x = \frac{- 33 + 31}{2 \cdot 8} : - \frac{1}{8}

x = \frac{- 33 - 31}{2 \cdot 8} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{8}, x = - 4

8 x^{2} - 7 x + 3 = 0

5 x^{2} + 30 x + 24 = 64

6 x^{2} - 25 x + 24 = 0

t, y = v t + \frac{1}{2} a t^{2}

x^{2} + 11 x - 276 = 0

What are the solutions to the equation 8x^2+33x+4=0 ?
The solutions to the equation 8x^2+33x+4=0 are x=-1/8 ,x=-4
Find the zeros of 8x^2+33x+4=0
The zeros of 8x^2+33x+4=0 are x=-1/8 ,x=-4