What are the solutions to the equation 4(x-1)^2=0 ?

The solutions to the equation 4(x-1)^2=0 are x=1

Find the zeros of 4(x-1)^2=0

The zeros of 4(x-1)^2=0 are x=1

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4 (x - 1)^{2} = 0

x = 1

Solution steps

4 (x - 1)^{2} = 0

Divide both sides by

4

(x - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x - 1 = 0 : x = 1

The solution to the quadratic equation is:

x = 1

- 1 = 0.95831 (t) + \frac{1}{2} (- 9.8) t^{2}

x^{2} - 17 = 8

x^{2} + 2 x + 10 = - x^{2} + x + 46

x, x^{2} - x y + y^{2} = 4

(3 x - 1) (x + 2) + 5 x = (2 x + 1) (x - 3)

What are the solutions to the equation 4(x-1)^2=0 ?
The solutions to the equation 4(x-1)^2=0 are x=1
Find the zeros of 4(x-1)^2=0
The zeros of 4(x-1)^2=0 are x=1