What are the solutions to the equation x^2-2x-2=5 ?

The solutions to the equation x^2-2x-2=5 are x=1+2sqrt(2),x=1-2sqrt(2)

Find the zeros of x^2-2x-2=5

The zeros of x^2-2x-2=5 are x=1+2sqrt(2),x=1-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x - 2 = 5

x = 1 + 22, x = 1 - 22

Decimal Notation

x = 3.82842 \dots, x = - 1.82842 \dots

Solution steps

x^{2} - 2 x - 2 = 5

Move

5

to the left side

x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 7) = 42

x_{1, 2} = \frac{- ( - 2 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 2}{2 \cdot 1} : 1 + 22

x = \frac{- ( - 2 ) - 4 2}{2 \cdot 1} : 1 - 22

The solutions to the quadratic equation are:

x = 1 + 22, x = 1 - 22

- x^{2} + 4 x + 6

x^{2} - 2 x + 193 = 0

8 (x^{2} + 4) - 2 x - 2 = 2 x^{2} - 5 x + 30

x \cdot x + 4 = x + 2 \cdot x + 1

x^{2} - 2 x - 35 = 0

What are the solutions to the equation x^2-2x-2=5 ?
The solutions to the equation x^2-2x-2=5 are x=1+2sqrt(2),x=1-2sqrt(2)
Find the zeros of x^2-2x-2=5
The zeros of x^2-2x-2=5 are x=1+2sqrt(2),x=1-2sqrt(2)