What are the solutions to the equation solvefor x,z=x^2+2y^2 ?

The solutions to the equation solvefor x,z=x^2+2y^2 are x=sqrt(z-2y^2),x=-sqrt(z-2y^2)

Find the zeros of solvefor x,z=x^2+2y^2

The zeros of solvefor x,z=x^2+2y^2 are x=sqrt(z-2y^2),x=-sqrt(z-2y^2)

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solve for

x, z = x^{2} + 2 y^{2}

x = z - 2 y^{2}, x = - z - 2 y^{2}

Solution steps

z = x^{2} + 2 y^{2}

Switch sides

x^{2} + 2 y^{2} = z

Move

2 y^{2}

to the right side

x^{2} = z - 2 y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = z - 2 y^{2}, x = - z - 2 y^{2}

3 r^{2} + 6 r + 1 = 0

y^{2} + 2 y - 80 = 0

3 x^{2} - 4 x + 1 = 2 x^{2} + 3 x - 4

x^{2} - 1 = 29

x^{2} - 1 = 10

What are the solutions to the equation solvefor x,z=x^2+2y^2 ?
The solutions to the equation solvefor x,z=x^2+2y^2 are x=sqrt(z-2y^2),x=-sqrt(z-2y^2)
Find the zeros of solvefor x,z=x^2+2y^2
The zeros of solvefor x,z=x^2+2y^2 are x=sqrt(z-2y^2),x=-sqrt(z-2y^2)