What are the solutions to the equation 21x^2+11x=2 ?

The solutions to the equation 21x^2+11x=2 are x= 1/7 ,x=-2/3

Find the zeros of 21x^2+11x=2

The zeros of 21x^2+11x=2 are x= 1/7 ,x=-2/3

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21 x^{2} + 11 x = 2

x = \frac{1}{7}, x = - \frac{2}{3}

Decimal Notation

x = 0.14285 \dots, x = - 0.66666 \dots

Solution steps

21 x^{2} + 11 x = 2

Move

2

to the left side

21 x^{2} + 11 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 21 ( - 2 )}{2 \cdot 21}

1 1^{2} - 4 \cdot 21 (- 2) = 17

x_{1, 2} = \frac{- 11 \pm 17}{2 \cdot 21}

Separate the solutions

x_{1} = \frac{- 11 + 17}{2 \cdot 21}, x_{2} = \frac{- 11 - 17}{2 \cdot 21}

x = \frac{- 11 + 17}{2 \cdot 21} : \frac{1}{7}

x = \frac{- 11 - 17}{2 \cdot 21} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{7}, x = - \frac{2}{3}

2 x = 3 x^{2}

2 x^{2} + 2 x = 4

\frac{x}{1000} = \frac{1}{2} (0.005) (6.5 - x - 0.5)^{2}

4 t^{2} + 2 t - 2 = 0

8 x^{2} - 2 x - 9 = 10

What are the solutions to the equation 21x^2+11x=2 ?
The solutions to the equation 21x^2+11x=2 are x= 1/7 ,x=-2/3
Find the zeros of 21x^2+11x=2
The zeros of 21x^2+11x=2 are x= 1/7 ,x=-2/3