What are the solutions to the equation -4.9x^2+26x=0 ?

The solutions to the equation -4.9x^2+26x=0 are x=0,x= 260/49

Find the zeros of -4.9x^2+26x=0

The zeros of -4.9x^2+26x=0 are x=0,x= 260/49

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- 4.9 x^{2} + 26 x = 0

x = 0, x = \frac{260}{49}

Decimal Notation

x = 0, x = 5.30612 \dots

Solution steps

- 4.9 x^{2} + 26 x = 0

Multiply both sides by

10

- 49 x^{2} + 260 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 260 \pm 26 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

26 0^{2} - 4 (- 49) \cdot 0 = 260

x_{1, 2} = \frac{- 260 \pm 260}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 260 + 260}{2 ( - 49 )}, x_{2} = \frac{- 260 - 260}{2 ( - 49 )}

x = \frac{- 260 + 260}{2 ( - 49 )} : 0

x = \frac{- 260 - 260}{2 ( - 49 )} : \frac{260}{49}

The solutions to the quadratic equation are:

x = 0, x = \frac{260}{49}

8^{2} + x^{2} = 6^{2}

x^{2} + b x - 18 = 0

5 z^{2} - 8 (- 3) z - 46 z + 5 (- 3)^{2} + 30 (- 3) + 62 = 0

x^{2} + 5 x = 40

5 x^{2} + 2 x - 16 = 0

What are the solutions to the equation -4.9x^2+26x=0 ?
The solutions to the equation -4.9x^2+26x=0 are x=0,x= 260/49
Find the zeros of -4.9x^2+26x=0
The zeros of -4.9x^2+26x=0 are x=0,x= 260/49