What are the solutions to the equation t^2+30t=-17 ?

The solutions to the equation t^2+30t=-17 are t=-15+4sqrt(13),t=-15-4sqrt(13)

Find the zeros of t^2+30t=-17

The zeros of t^2+30t=-17 are t=-15+4sqrt(13),t=-15-4sqrt(13)

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t^{2} + 30 t = - 17

t = - 15 + 413, t = - 15 - 413

Decimal Notation

t = - 0.57779 \dots, t = - 29.42220 \dots

Solution steps

t^{2} + 30 t = - 17

Move

17

to the left side

t^{2} + 30 t + 17 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

3 0^{2} - 4 \cdot 1 \cdot 17 = 813

t_{1, 2} = \frac{- 30 \pm 8 13}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 30 + 8 13}{2 \cdot 1}, t_{2} = \frac{- 30 - 8 13}{2 \cdot 1}

t = \frac{- 30 + 8 13}{2 \cdot 1} : - 15 + 413

t = \frac{- 30 - 8 13}{2 \cdot 1} : - 15 - 413

The solutions to the quadratic equation are:

t = - 15 + 413, t = - 15 - 413

2 x (4 x - 1) = 7

x^{2} - x = 24

x^{2} - x = - 6

k^{2} = 21

x^{2} - 16 x + 8 = 0

What are the solutions to the equation t^2+30t=-17 ?
The solutions to the equation t^2+30t=-17 are t=-15+4sqrt(13),t=-15-4sqrt(13)
Find the zeros of t^2+30t=-17
The zeros of t^2+30t=-17 are t=-15+4sqrt(13),t=-15-4sqrt(13)