What are the solutions to the equation 16x^2-48x+36=0 ?

The solutions to the equation 16x^2-48x+36=0 are x= 3/2

Find the zeros of 16x^2-48x+36=0

The zeros of 16x^2-48x+36=0 are x= 3/2

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16 x^{2} - 48 x + 36 = 0

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

16 x^{2} - 48 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 16 \cdot 36}{2 \cdot 16}

(- 48)^{2} - 4 \cdot 16 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 48 )}{2 \cdot 16}

\frac{- ( - 48 )}{2 \cdot 16} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

3 (x + 6) (x - 2) = 0

300 - 4.9 t^{2} = 0

x, 2 - 2 x - 3 x^{2} = 0

7^{2} = 4^{2} + x^{2}

p^{2} + 0 = 0

What are the solutions to the equation 16x^2-48x+36=0 ?
The solutions to the equation 16x^2-48x+36=0 are x= 3/2
Find the zeros of 16x^2-48x+36=0
The zeros of 16x^2-48x+36=0 are x= 3/2