What are the solutions to the equation -x^2-x+7=0 ?

The solutions to the equation -x^2-x+7=0 are x=-(1+sqrt(29))/2 ,x=(sqrt(29)-1)/2

Find the zeros of -x^2-x+7=0

The zeros of -x^2-x+7=0 are x=-(1+sqrt(29))/2 ,x=(sqrt(29)-1)/2

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- x^{2} - x + 7 = 0

x = - \frac{1 + 29}{2}, x = \frac{29 - 1}{2}

Decimal Notation

x = - 3.19258 \dots, x = 2.19258 \dots

Solution steps

- x^{2} - x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 7 = 29

x_{1, 2} = \frac{- ( - 1 ) \pm 29}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 29}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 29}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 29}{2 ( - 1 )} : - \frac{1 + 29}{2}

x = \frac{- ( - 1 ) - 29}{2 ( - 1 )} : \frac{29 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 29}{2}, x = \frac{29 - 1}{2}

x, u = x^{2} + y^{2}

3 (x + 2)^{2} - 15 = 0

9 x^{2} - 9 x = 0

x (x - 2) = x + 4

7000 - 2 Q = 0.1 Q^{2} + 2 Q + 1000

What are the solutions to the equation -x^2-x+7=0 ?
The solutions to the equation -x^2-x+7=0 are x=-(1+sqrt(29))/2 ,x=(sqrt(29)-1)/2
Find the zeros of -x^2-x+7=0
The zeros of -x^2-x+7=0 are x=-(1+sqrt(29))/2 ,x=(sqrt(29)-1)/2