What are the solutions to the equation 12x-0.24x^2=0 ?

The solutions to the equation 12x-0.24x^2=0 are x=0,x=50

Find the zeros of 12x-0.24x^2=0

The zeros of 12x-0.24x^2=0 are x=0,x=50

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12 x - 0.24 x^{2} = 0

x = 0, x = 50

Solution steps

12 x - 0.24 x^{2} = 0

Multiply both sides by

100

1200 x - 24 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 24 x^{2} + 1200 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1200 \pm 120 0 ^{2} - 4 ( - 24 ) \cdot 0}{2 ( - 24 )}

120 0^{2} - 4 (- 24) \cdot 0 = 1200

x_{1, 2} = \frac{- 1200 \pm 1200}{2 ( - 24 )}

Separate the solutions

x_{1} = \frac{- 1200 + 1200}{2 ( - 24 )}, x_{2} = \frac{- 1200 - 1200}{2 ( - 24 )}

x = \frac{- 1200 + 1200}{2 ( - 24 )} : 0

x = \frac{- 1200 - 1200}{2 ( - 24 )} : 50

The solutions to the quadratic equation are:

x = 0, x = 50

x^{2} + 8 x - 20

A, A^{2} - Y = CB

5 a^{2} = 45

d, h = - 0.13 d (d - 20)

y^{2} - 4 y = - 5

What are the solutions to the equation 12x-0.24x^2=0 ?
The solutions to the equation 12x-0.24x^2=0 are x=0,x=50
Find the zeros of 12x-0.24x^2=0
The zeros of 12x-0.24x^2=0 are x=0,x=50